I'm wondering how you could compare two boxed integers (either can be signed or unsigned) to each other for equality.
For instance, take a look at this scenario:
// case #1
object int1 = (int)50505;
object int2 = (int)50505;
bool success12 = int1.Equals(int2); // this is true. (pass)
// case #2
int int3 = (int)50505;
ushort int4 = (ushort)50505;
bool success34 = int3.Equals(int4); // this is also true. (pass)
// case #3
object int5 = (int)50505;
object int6 = (ushort)50505;
bool success56 = int5.Equals(int6); // this is false. (fail)
I'm stumped on how to reliably compare boxed integer types this way. I won't know what they are until runtime, and I can't just cast them both to long
, because one could be a ulong
. I also can't just convert them both to ulong
because one could be negative.
The best idea I could come up with is to just trial-and-error-cast until I can find a common type or can rule out that they're not equal, which isn't an ideal solution.
In case 2, you actually end up calling int.Equals(int)
, because ushort
is implicitly convertible to int
. This overload resolution is performed at compile-time. It's not available in case 3 because the compiler only knows the type of int5
and int6
as object
, so it calls object.Equals(object)
... and it's natural that object.Equals
will return false
if the types of the two objects are different.
You could use dynamic typing to perform the same sort of overload resolution at execution time - but you'd still have a problem if you tried something like:
dynamic x = 10;
dynamic y = (long) 10;
Console.WriteLine(x.Equals(y)); // False
Here there's no overload that will handle long
, so it will call the normal object.Equals
.
One option is to convert the values to decimal
:
object x = (int) 10;
object y = (long) 10;
decimal xd = Convert.ToDecimal(x);
decimal yd = Convert.ToDecimal(y);
Console.WriteLine(xd == yd);
This will handle comparing ulong
with long
as well.
I've chosen decimal
as it can exactly represent every value of every primitive integer type.
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