why does the compiler doesn't give error while assigning long to float?

when i execute the below code, i expected it to get warning "can't convert from long to float" because the float is 32 bits and long is 64 bits in size. But looks like no warning, Could anyone explain me how?

public static void main(String[] args)
{
    float a=1;
    long b=123;
     a=b;
    System.out.println(a);
}
Jon Skeet
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The range of float is much larger than the range of long... there's an implicit conversion which may lose precision, but not magnitude. The same is true for long to double.

From JLS 5.1.2:

A widening primitive conversion from int to float, or from long to float, or from long to double, may result in loss of precision - that is, the result may lose some of the least significant bits of the value. In this case, the resulting floating-point value will be a correctly rounded version of the integer value, using IEEE 754 round-to-nearest mode (ยง4.2.4).

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