Java: What happens to the supposed to be initialized members when passing a value to their object at creation time?

This question is more about having a proper Java program construction. I was wondering: What happens to the 

public Clazz { 
   this.someClazz = new SomeClazz(); 
}  //initialization

Clazz x = y;

Is the above constructor gets executed, or is it skipped, and someClazz memberget a new value right away?

Jon Skeet
people
quotationmark

You need to distinguish between variables, objects and references.

The values of x and y are not objects - they're just references. The assignment operator just copies the value from the expression on the right to the variable on the left. So in your case, it copies the value of y into x... at that point, the values of both variables refer to the same object. No constructors or any other members get called - it's just copying a value. So for example:

// Assuming appropriate methods...
x.setFoo("new foo");
System.out.println(y.getFoo()); // Would print "new foo"

However, the two variables are still independent:

x.setFoo("new foo");
x = new Clazz();
x.setFoo("yet another foo");
System.out.println(y.getFoo()); // Would print "new foo"

Here, after the second line, the values of x and y refer to different objects, so calling x.setFoo() doesn't change the value of foo within the object that y refers to.

people

See more on this question at Stackoverflow