StringTokenizer array

Java. So I want to input an array of integers and then print out the max value using StringTokenizer. I know how to do this using integers, but when I try to do it with an array the String to int command (Integer.parseInt) fails me - cannot convert from int to int[].

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        String strTmp;
        StringTokenizer strTok;
        while ((strTmp = in.readLine()) != null && strTmp.length() != 0) {
            strTok = new StringTokenizer(strTmp);

        int[] c;

        c = Integer.parseInt(strTok.nextToken());

        int max = 0;
        for (int i = 0; i < c.length; i++) {
            if (c[i] > max) {
                max = c[i];
            }
        }
        System.out.println(max);
    }
}
}

How do I go about solving this or are there other commands I should be using?

Jon Skeet
people
quotationmark

You seem to be confused about whether you actually want an array or not. You're parsing a single value, but trying to assign that int to c which is an array variable. You don't really need one, as you only need to remember the current maximum, and the value you've just parsed:

int max = Integer.MIN_VALUE;
while (strTok.hasMoreTokens()) {
    int value = Integer.parseInt(strTok.nextToken());
    if (value > max) {
        max = value;
    }
}

If you really want an array, then you'll need to know how many tokens there are before you parse them, which is tricky.

Another alternative would be to create a List<Integer>:

// First parse everything...
List<Integer> values = new ArrayList<>();
while (strTok.hasMoreTokens()) {
    values.add(Integer.parse(strTok.nextToken());
}

// Then you can find the maximum value in the list

Personally I prefer the first approach, if you only need to find the maximum value.

people

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